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Latex syntax date added Equation
m_{\rm BH}\propto U \propto \frac{GM_{\rm halo}^2}{r_{\rm halo}}\propto m_{\rm halo}^{5/3}2009-11-07 06:30:50
m_{\rm BH}\propto U \propto \frac{GM_{\rm halo}}{r{\rm halo}}2009-11-07 06:30:15
C. Desviacion Estandar= \sqrt[2 ]{ \frac{ \left (46.8-47.8 \right ) { }^{2 }+ \left (47.4-47.8 \right ) { }^{2 } }{ } } 2009-11-07 05:40:19
\left ( \right ) 2009-11-07 05:37:34
\left ( \right ) 2009-11-07 05:37:32
Promedio % KHP= \frac{46.8% + 47.4% + 49.1% }{3 }= 47.8% KHP2009-11-07 05:34:44
F = G \dfrac{m_1 m_2}{r^2}2009-11-07 03:37:26
\int_{a}2009-11-07 01:44:32
\int_{a}2009-11-07 01:44:25
f=\frac{V L}{v}2009-11-06 23:57:26
f=\frac{V L}{v}2009-11-06 23:57:04
f=\frac{V L}{v}2009-11-06 23:55:54
f=\frac{V L}{v}2009-11-06 23:54:13
\frac{vol. titulante L(molaridad)( \frac{ 1 mol KHP}{1 mol NaOH })( \frac{ MW KHP}{1 mol Cl } ) }{ g de muestra} 2009-11-06 18:28:27
s= \sqrt[ ]{ \frac{ { ()}^{2 }+ { ()}^{2 } + {() }^{2 } }{2 } } = %2009-11-06 17:11:32
s= \sqrt[ ]{ \frac{ { ()}^{2 } }{2 } } = %2009-11-06 17:10:53
KHP= \frac{L \left ( \frac{ molesNaOH}{L } \right ) \left ( \frac{ 1molKHP}{1molNaOH } \right ) \left ( \frac{ 204.14gKHP}{1molKHP } \right ) }{g muestra } x 1002009-11-06 17:05:54
KHP= \frac{L \left ( \frac{ molesNaOH}{L } \right ) \left ( \frac{ 1molKHP}{1molNaOH } \right ) }{g muestra } 2009-11-06 17:04:39
KHP= \frac{L \frac{molesNaOH }{ L} \frac{1molKHP }{1molNaOH } }{ g muestra} 2009-11-06 17:02:41
KHP= \frac{L \frac{molesNaOH }{ L} \frac{1molKHP }{1molNaOH } }{ g muestra} 2009-11-06 17:02:41

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